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From: =?ISO-8859-1?Q?Hibou57_=28Yannick_Duch=EAne=29?=
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Newsgroups: comp.lang.ada
Subject: Re: How to convert a string containing two hex digits to a character?
Date: Sat, 9 Jan 2010 02:50:14 -0800 (PST)
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Date: 2010-01-09T02:50:14-08:00
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On 6 jan, 23:19, Hibou57 (Yannick Duch=EAne) <yannick_duch...@yahoo.fr>
wrote:
> On 6 jan, 22:54, Maciej Sobczak <see.my.homep...@gmail.com> wrote:
>
> > Sorry, but I find it to be overly paranoid.
> > What has happened to the old good "Something + 1"?
>
> No such thing as paranoia here, as any way, for numbers, X + 1 and
> Number_Type'Succ (X) are strictly equivalent (thus, the Succ function
> attribute is not more paranoid than the =93 + =94 operator).
>
> As the question was from a student, I was just trying to give him/her
> some food for dinner. It's always good to know about Succ : it is
> required with enumerated types, and it is the only way to do something
> like =93 + 1 =94 when a numeric type is passed as a formal discrete type
> parameter of a generic.

Number_Type'Pred and Number_Type'Succ are also useful when just
increment are decrement are to be done on type whose standard
operators are not visible. It allows to do this computation without
even requiring a "use type".