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From: "Shawn M. Root" <sroot@ems.jsc.nasa.gov>
Subject: Re: Problem with operator "<"
Date: 2000/09/17
Message-ID: <8q41tt$sk9@niven.ksc.nasa.gov>#1/1
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References: <39C12B38.47273C93@netcourrier.com> <8prggo$q9k$1@nnrp1.deja.com>
 <39C25377.E038D6C9@netcourrier.com> <39C2ADEC.10E0B022@swbell.net>
 <39C36424.C88A764@netcourrier.com> <39C3A4A8.9ED2F23F@swbell.net>
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Date: 2000-09-17T00:00:00+00:00
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"John Magness" <jmagness@swbell.net> wrote in message
news:39C3A4A8.9ED2F23F@swbell.net...
>
>
> Mathias Dolidon wrote:
>
> > > My two cents --  the line :  if Left(i) < Right(i) then  appears
to be
> > > comparing the same element of the array.
> > > This line should never test true.
> >
> > It isn't the same array. I don't understand what problem you see
here...
>
> Sorry -- my mistake -- it is not the same array.  However it is
still a
> recursive call to the function being declared ("<") is it not?
>
> If the line is changed to "if not (left(i) > right(i)) then " the
recursive
> call would
> be avoided.
> John
>
There is no recursion here. The line if Left(i) < Right(i) then  uses
the "<" operator for whatever type comprises the elements of a
grand_entier.  Also, you might want to think about your solution for
solving the problem.  not (left>right) is not the same as
(left<right).

Shawn M. Root