From mboxrd@z Thu Jan 1 00:00:00 1970 X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me X-Spam-Level: * X-Spam-Status: No, score=1.3 required=5.0 tests=BAYES_00,INVALID_MSGID, MSGID_RANDY autolearn=no autolearn_force=no version=3.4.4 X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 103376,bf8094bb47ac6c34 X-Google-Attributes: gid103376,public From: Robert Dewar Subject: Re: Loops Date: 2000/05/27 Message-ID: <8go596$ms6$1@nnrp1.deja.com>#1/1 X-Deja-AN: 627896267 References: <8gntbt$mei$3@news.cowan.edu.au> X-Http-Proxy: 1.0 x64.deja.com:80 (Squid/1.1.22) for client 205.232.38.14 Organization: Deja.com - Before you buy. X-Article-Creation-Date: Sat May 27 09:41:59 2000 GMT X-MyDeja-Info: XMYDJUIDrobert_dewar Newsgroups: comp.lang.ada X-Http-User-Agent: Mozilla/4.61 [en] (OS/2; I) Date: 2000-05-27T00:00:00+00:00 List-Id: In article <8gntbt$mei$3@news.cowan.edu.au>, "Karlene" wrote: > If the exit condition for the loop of a subprogram is the word "stop" when > written in a string field (ie a persons name), how can you code that? Simply test to see if the string contains the characters "stop". If you don't know how to do this, you need to start with the basics, and study either your text book, or go through one of the online tutorials. Sent via Deja.com http://www.deja.com/ Before you buy.