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From: Keith Thompson <Keith.S.Thompson+u@gmail.com>
Newsgroups: comp.lang.ada
Subject: Re: [ANN] GCC 14.2.0-3 (aarch64, macOS)
Date: Sat, 30 Nov 2024 13:15:24 -0800
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Keith Thompson <Keith.S.Thompson+u@gmail.com> writes:
> Simon Wright <simon@pushface.org> writes:
>> Björn Persson <Bjorn@rombobjörn.se> writes:
>>> It happened today in GCC 14.2.1 (as packaged in Fedora 41), so no, not
>>> only in 14.2.0.
>>
>> There's no official FSF 14.2.1 release - it may just be like Alire,
>> which only handles 3 levels, so they call the first packaging of 14.2.0
>> 14.2.1. If you say 'gcc -v' it'll probably say 14.2.0.
>>
>> Of course I could be completely wrong and Fedora have added lots of
>> value!
>
> I see some potential for confusion, since there almost certainly will be
> an official gcc 14.2.1 release in the near future.  That official
> release will include code that's not included in what Fedora calls gcc
> 14.2.1.  It's a point release, so I wouldn't expect substantial changes,
> but still, I think Fedora should use a different naming scheme.

After I wrote the above, I built gcc from its git repo, using the tip
of the releases/gcc-14 branch (not a release tag).  Presumably the
Fedora folks did something similar.  The resulting gcc reports its
own version as :

    $ gcc --version
    gcc (GCC) 14.2.1 20241129

whereas a gcc built from the releases/gcc-14.2.0 tag reports :

    $ gcc --version
    gcc (GCC) 14.2.0

with no date.

I still see some potential for confusion, but not as much as I initially
thought.  (The fact that gcc doesn't do *.*.1 releases is fairly
obscure, and I wouldn't expect most people to know about it.)

-- 
Keith Thompson (The_Other_Keith) Keith.S.Thompson+u@gmail.com
void Void(void) { Void(); } /* The recursive call of the void */