From mboxrd@z Thu Jan 1 00:00:00 1970 X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me X-Spam-Level: X-Spam-Status: No, score=-1.3 required=5.0 tests=BAYES_00,INVALID_MSGID autolearn=no autolearn_force=no version=3.4.4 X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 103376,7f057fd3e6878bac,start X-Google-Attributes: gid103376,public From: "Igor Izvarin" Subject: Command line parameters Date: 1999/01/17 Message-ID: <77tm5p$kls$1@scelto.ts.kiev.ua>#1/1 X-Deja-AN: 433764246 X-MimeOLE: Produced By Microsoft MimeOLE V4.72.3110.3 X-Complaints-To: usenet@scelto.ts.kiev.ua X-Trace: scelto.ts.kiev.ua 916610041 21180 194.183.165.19 (17 Jan 1999 21:54:01 GMT) Organization: "Relcom-Ukraine" (tm) ISP NNTP-Posting-Date: 17 Jan 1999 21:54:01 GMT Newsgroups: comp.lang.ada Date: 1999-01-17T21:54:01+00:00 List-Id: Hi, Could anybody explain me how I can obtain filename parameter from command line: programe.exe -a -b -c120 -d240 filename.ext because FILENAME: STRING(1..80); FILENAME := ARGUMENT(I); doesnot work weel and I do not know exact length of filename.ext parameter. I am using ObectAda compiler.