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From: tonyg <tonythegair@googlemail.com>
Newsgroups: comp.lang.ada
Subject: Re: Unbounded String to string
Date: Wed, 30 Jun 2010 01:28:50 -0700 (PDT)
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Date: 2010-06-30T01:28:50-07:00
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On 29 June, 16:19, Adam Beneschan <a...@irvine.com> wrote:
> On Jun 29, 8:08=A0am, Ludovic Brenta <ludo...@ludovic-brenta.org> wrote:
>
>
>
>
>
> > tonyg wrote on comp.lang.ada:
>
> > > On 29 June, 15:33, Adam Beneschan <a...@irvine.com> wrote:
> > >> On Jun 29, 7:28=A0am, tonyg <tonytheg...@googlemail.com> wrote:
>
> > >>> Hi,
> > >>> =A0 =A0I have an unbounded string from a database I want to turn in=
to a 16
> > >>> character subtype of string
>
> > >>> i.e. unbounded_string to string(1..16)
>
> > >>> I've been trying to do this most of the afternoon but keep getting
> > >>> errors
>
> > >>> anyone know how ?
>
> > >> Declare a subtype to give string(1..16) a name; then call To_String
> > >> (in Ada.Strings.Unbounded) and convert the function result to your
> > >> subtype. =A0E.g.:
>
> > >> =A0 =A0subtype String_Length_16 is string(1..16);
> > >> =A0 =A0V : String_Length_16;
>
> > >> =A0 =A0V :=3D String_Length_16 (Ada.Strings.Unbounded.To_String (U))=
;
>
> > That solution only works if U happens to contain exactly 16
> > characters, which is probably not the case if the database really
> > contains unbounded strings (i.e. VARCHAR or similar).
>
> Right, when the OP said he wanted to "turn [an unbounded string] into
> a 16 character subtype", I didn't look more deeply into the words
> "turn into". =A0I suppose I should have. =A0We'd need to know exactly wha=
t
> his requirements are to provide a full solution, though---
> specifically, does he expect any unbounded strings to be shorter than
> 16 characters, does he expect any of them to be longer than 16
> characters, and if either or both is "yes", what it the desired
> behavior in each case.
>
> =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0 =A0-- Adam

I never knew either way and its the first time I have been taking a
string from a database - believe it or not all the rest have been
numbers up to now :) but thanks to the both of you for your help.