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From: Ada novice <ycalleecharan@gmx.com>
Newsgroups: comp.lang.ada
Subject: Re: understanding floating point types
Date: Tue, 24 Aug 2010 05:14:44 -0700 (PDT)
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Date: 2010-08-24T05:14:44-07:00
List-Id: <comp.lang.ada>

I have just read the following from an Ada book by Fintan Culwin:
----
type VeryAccurate is digits 16
type NotAccurate is digits 2

Values of the type VeryAccurate would have limited range with a high
degree of precision. Values of the type NotAccurate would have a much
greater range with only two digits of precision.
----

My understanding is that using "B = 3.32*D + 1", a type with digits 16
(D = 16) will have a higher B value and hence a higher exponent range
-4*B to 4*B than a type with digits 2. Will a higher exponent range
not give a higher range?

What am I understanding wrong here?

Thanks
YC