From mboxrd@z Thu Jan 1 00:00:00 1970 X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me X-Spam-Level: X-Spam-Status: No, score=0.2 required=5.0 tests=BAYES_00,INVALID_MSGID, REPLYTO_WITHOUT_TO_CC autolearn=no autolearn_force=no version=3.4.4 X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 109fba,df854b5838c3e14 X-Google-Attributes: gid109fba,public X-Google-Thread: 103376,df854b5838c3e14 X-Google-Attributes: gid103376,public X-Google-Thread: 10db24,fec75f150a0d78f5 X-Google-Attributes: gid10db24,public X-Google-Thread: 1014db,df854b5838c3e14 X-Google-Attributes: gid1014db,public From: seebs@solutions.solon.com (Peter Seebach) Subject: Re: ANSI C and POSIX (was Re: C/C++ knocks the crap out of Ada) Date: 1996/04/10 Message-ID: <4kh596$ook@solutions.solon.com>#1/1 X-Deja-AN: 146784887 references: <4kcpgkINNcku@keats.ugrad.cs.ubc.ca> <4kgunm$o4o@gde.GDEsystems.COM> organization: Usenet Fact Police (Undercover) reply-to: seebs@solon.com newsgroups: comp.lang.ada,comp.lang.c,comp.lang.c++,comp.edu Date: 1996-04-10T00:00:00+00:00 List-Id: In article <4kgunm$o4o@gde.GDEsystems.COM>, Chet wrote: [re: after 'int i, j;', is &i+1 == &j?] >If i = j depends on your unit of address. If i is assumed a longword then > &i + 4 = &j is true > not > &i + 1 = &j This is stupid. A compiler may order the objects in any order it wishes, unless they're in a struct, in which case they must be in declaration order, but there may be arbitrary padding if they're in a struct. But the main stupidity here is that, if i is a longword, &i+1 is one longword "up" from i. Please refrain from correcting my april fools' posting unless you know C, preferably reasonably well. -s -- Peter Seebach - seebs@solon.com - Copyright 1996 Peter Seebach. C/Unix wizard -- C/Unix questions? Send mail for help. No, really! FUCK the communications decency act. Goddamned government. [literally.] The *other* C FAQ - http://www.solon.com/~seebs/c/c-iaq.html