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NNTP-Posting-Date: Wed, 14 Jan 2009 15:41:29 -0600
From: Brian Drummond <brian_drummond@btconnect.com>
Newsgroups: comp.lang.ada
Subject: Re: How to put 200 into an integer sub-type of 16 bits (code
  included)
Date: Wed, 14 Jan 2009 21:51:02 +0000
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Date: 2009-01-14T21:51:02+00:00
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On Wed, 14 Jan 2009 12:13:29 -0800 (PST), ChristopherL
<clusardi2k@aol.com> wrote:


>
>I want to copy bits from an Ada float to a user defined short integer
>maintaining the same
>bit representation.

FROM a Float? This is the first time you have said that.

Now - assuming SP float, which bits? You have 32 to choose from, and you
alternate between wanting 16 bits (last time) and 8 bits (as here).

But you still  ha you want:
(a) the top 8 bits?
(b) the bottom 8 bits?
(c) the exponent?
(d) the top 8 bits of the mantissa,
(e) an integer representation (200) of the input Float _value_ (200.0)
instead of its _bit_pattern_
(f) something else altogether
>
>Arg:Float;  -- From this with a value of 200
>subtype Short_integer is Integer range -(2 ** 7) .. ((2 ** 7) - 1 );
>Result: Short_integer; --to this, and I want to round Arg

If (e) you have 2 options:

(1) for 8 bits you need an unsigned integer, e.g. 
subtype Short_integer is Natural range 0 .. ((2 ** 8) - 1 );

(2) for 16 bits, either signed or unsigned will work.
subtype Short_integer is Integer range -(2 ** 15) .. ((2 ** 15) - 1 );

In either case, all you need is
Result: Short_integer := Short_integer(Arg + 0.5);
Of course it may well round up to 201...

- Brian