From mboxrd@z Thu Jan 1 00:00:00 1970 X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me X-Spam-Level: X-Spam-Status: No, score=-1.9 required=5.0 tests=BAYES_00,FREEMAIL_FROM autolearn=unavailable autolearn_force=no version=3.4.4 X-Received: by 10.224.18.132 with SMTP id w4mr8326373qaa.1.1364280575453; Mon, 25 Mar 2013 23:49:35 -0700 (PDT) X-Received: by 10.49.127.50 with SMTP id nd18mr907739qeb.6.1364280575440; Mon, 25 Mar 2013 23:49:35 -0700 (PDT) Path: eternal-september.org!reader01.eternal-september.org!reader02.eternal-september.org!news.eternal-september.org!news.eternal-september.org!mx05.eternal-september.org!feeder.eternal-september.org!news.glorb.com!ca1no7554413qab.0!news-out.google.com!k8ni11100qas.0!nntp.google.com!ca1no7554404qab.0!postnews.google.com!glegroupsg2000goo.googlegroups.com!not-for-mail Newsgroups: comp.lang.ada Date: Mon, 25 Mar 2013 23:49:35 -0700 (PDT) Complaints-To: groups-abuse@google.com Injection-Info: glegroupsg2000goo.googlegroups.com; posting-host=24.74.165.254; posting-account=OorKfwoAAAAEG64-jj7QakHqbp6ymd2J NNTP-Posting-Host: 24.74.165.254 User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <415102ba-2bb4-4576-a164-806318db062f@googlegroups.com> Subject: Three of a crime. From: gattamaneni abhiram Injection-Date: Tue, 26 Mar 2013 06:49:35 +0000 Content-Type: text/plain; charset=ISO-8859-1 Xref: news.eternal-september.org comp.lang.ada:14718 Date: 2013-03-25T23:49:35-07:00 List-Id: Three-of-a-crime is a simple logic game for up to 3 players. There are 7 different criminals. The computer randomly chooses three of these (the "perpetrators"), but doesn't tell the players which are chosen. The computer then puts down three random criminals. 0, 1, or 2 of these may be the actual perpetrators. The computer also tells the player how many (but not which) of the three criminals are perpetrators. The players may either guess which three criminals are the actual perpetrators or they may pass. If a player guesses wrong, she is out of the game and the other players continue. If no player chooses to guess, the computer puts down another three randomly chosen criminals (0, 1, or 2 of which may be actual perpetrators) and tells the players how many (but not which) of these are actual perpetrators. Players can again use logic to deduce the three actual criminals and may guess. Play continues until some player guesses correctly or until all players have guessed incorrectly. I am not able to deduce the logic. Can anyone please help me with the logic?