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From: "DuckE" <nospam_steved@pacifier.com>
Subject: Re: Ada83 Exponentiation HELP !!!
Date: 1999/12/13
Message-ID: <3855ab32.0@news.pacifier.com>#1/1
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References: <831tka$rue$1@tobruk.sydney.gecm.com>
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Reply-To: "DuckE" <nospam_steved@pacifier.com>
Newsgroups: comp.lang.ada
Date: 1999-12-13T00:00:00+00:00
List-Id: <comp.lang.ada>

It's been years since I've dealt with evaluating things like this, but as I
recall 6^(1.3) is equivalent to:

   Exp( 1.3 * Log( 6 ) )

Don't quote me on this, but it's somehting like that.

SteveD

jxredi <jxredi@gecms.com.au> wrote in message
news:831tka$rue$1@tobruk.sydney.gecm.com...
> Can anyone help me with the following  :
>
> I understand that in Ada83,     6^3  is represented as 6**3, where 6 can
be
> int or real,
> and 3 can only be an INTEGER.
>
> So how do I represent in ada83 this .....  -->    6^(1.3) where 1.3 is
type
> REAL.
>
>
> Regards,
> Jxredi.
>
>