From mboxrd@z Thu Jan  1 00:00:00 1970
X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me
X-Spam-Level: 
X-Spam-Status: No, score=0.6 required=5.0 tests=BAYES_40,INVALID_MSGID
	autolearn=no autolearn_force=no version=3.4.4
X-Google-Language: ENGLISH,ASCII-7-bit
X-Google-Thread: 103376,fedc2d05e82c9174
X-Google-Attributes: gid103376,public
From: als0045 <als0045@v2.qub.ac.uk>
Subject: Re: Calculating SQRT in ADA
Date: 1999/03/26
Message-ID: <36FBCFAE.6F55@v2.qub.ac.uk>#1/1
X-Deja-AN: 459428958
Content-Transfer-Encoding: 7bit
References: <auWJ2.6969$2G6.3578@c01read02.service.talkway.com>
 <01be7613$c90ed040$0e2915c0@w95> <36F94393.5D1B317D@icon.fi>
 <36FBACBB.4103@v2.qub.ac.uk>
Content-Type: text/plain; charset=us-ascii
Organization: Queen's University of Belfast
Mime-Version: 1.0
Newsgroups: comp.lang.ada
Date: 1999-03-26T00:00:00+00:00
List-Id: <comp.lang.ada>

als0045 wrote:
> 
> One trick is to calculate
> Inverse_Sqrt followed by one call to "/". 
No, dummy, just multiply your 1 / Sqrt(x) by x.

Come to think of it, One_Over_Sqrt(x) is a much better name for it.

--     Jonathan Parker 
--     Department of Applied Mathematics and Theoretical Physics
--     The Queen's University of Belfast