From mboxrd@z Thu Jan 1 00:00:00 1970 X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me X-Spam-Level: X-Spam-Status: No, score=-1.3 required=5.0 tests=BAYES_00,INVALID_MSGID autolearn=no autolearn_force=no version=3.4.4 X-Google-Language: ENGLISH,ASCII-7-bit X-Google-Thread: 103376,21162150cec9bc17,start X-Google-Attributes: gid103376,public From: "mincus" Subject: String Length Date: 1998/10/01 Message-ID: <36140400.0@news.cyberenet.net>#1/1 X-Deja-AN: 396848642 X-NNTP-Posting-Host: 204.213.252.15 Organization: CyberENET Network Service Provider Newsgroups: comp.lang.ada X-MimeOLE: Produced By Microsoft MimeOLE V4.72.3110.3 Date: 1998-10-01T00:00:00+00:00 List-Id: If anyone knows how to determine the size of a string I would be very grateful. I thought that I could do a string'last and that would return the position of the last char, but I just get an error, please help mincus