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From: =?ISO-8859-1?Q?Hibou57_=28Yannick_Duch=EAne=29?=
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Newsgroups: comp.lang.ada
Subject: Re: Question on Controlled types
Date: Thu, 4 Jun 2009 05:32:59 -0700 (PDT)
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Date: 2009-06-04T05:32:59-07:00
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On 30 mai, 15:27, "Dmitry A. Kazakov" <mail...@dmitry-kazakov.de>
wrote:
> The formula is I + A = F, where I is the number of calls to Initialize, A
> is the number of calls to Adjust and F is the number of calls to Finalize.
>
> Note that the compiler has right to optimize some pairs Adjust/Finalize
> away or add new ones.

So this means that if there was a second assignation of Delay1,
Finalize would be invoked before the copy and the Adjust which will
follow the copy ?

With one single assignation :

1) Delay1 assigned
2) Adjust invoked

3) Finalize invoked

With two assignations:

1) Delay1 assigned
2) Adjust invoked

3) Finalize invoked before copy
4) Delay1 assigned
5) Adjust invoked after copy

6) Finalize invoked

Is that right ?