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From: Phil Clayton <phil.clayton@lineone.net>
Newsgroups: comp.lang.ada
Subject: Re: Pascal Calling Convention
Date: Thu, 31 Mar 2011 00:40:54 -0700 (PDT)
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Date: 2011-03-31T00:40:54-07:00
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On Mar 30, 2:42=A0pm, Phil Clayton <phil.clay...@lineone.net> wrote:
> On Mar 29, 1:23 pm, stefan-lu...@see-the.signature wrote:
>
>
>
> > The original C++ from Hyman Rosen was
>
> > template <unsigned N>
> > class set
> > {
> > =A0 =A0 unsigned n; =A0 =A0// number of members in set
> > =A0 =A0 unsigned d[N]; // members are in d[0..n-1]
> > =A0 =A0 unsigned s[N]; // d[s[k]] =3D=3D k if k is a member
> > =A0 =A0 // unspecified elements of d and s are arbitrary
>
> > public:
> > =A0 =A0 set() : n(0) { }
> > =A0 =A0 bool has(unsigned k)
> > =A0 =A0 =A0 =A0 { return k < N && s[k] < n && d[s[k]] =3D=3D k; }
> > =A0 =A0 void add(unsigned k)
> > =A0 =A0 =A0 =A0 { if (k < N && !has(k)) { d[n] =3D k; s[k] =3D n++; }
> > =A0 =A0 void del(unsigned k)
> > =A0 =A0 =A0 =A0 { if (has(k)) { unsigned i =3D s[k]; d[i] =3D d[--n]; s=
[d[i]] =3D i; }
> > =A0 =A0 void clr() { n =3D 0; }
>
> > };
>
> Interesting. =A0It's worth noting that if N is equal to the number of
> keys representable by unsigned

Except that it can't be because N is also of type unsigned so there
can't be 'overflow' either. I didn't see that in the template
argument. Ignore me.

Phil