From mboxrd@z Thu Jan  1 00:00:00 1970
X-Spam-Checker-Version: SpamAssassin 3.4.4 (2020-01-24) on polar.synack.me
X-Spam-Level: 
X-Spam-Status: No, score=-1.9 required=5.0 tests=BAYES_00,FREEMAIL_FROM
	autolearn=ham autolearn_force=no version=3.4.4
X-Google-Language: ENGLISH,ASCII-7-bit
X-Google-Thread: 103376,937456e2dd44bde1,start
X-Google-Attributes: gid103376,public
X-Google-ArrivalTime: 2002-08-12 05:29:27 PST
Path: archiver1.google.com!postnews1.google.com!not-for-mail
From: vashwathus@yahoo.com (Ashwath)
Newsgroups: comp.lang.ada
Subject: Floating point representation-help
Date: 12 Aug 2002 05:29:27 -0700
Organization: http://groups.google.com/
Message-ID: <14763faf.0208120429.658b842d@posting.google.com>
NNTP-Posting-Host: 203.90.88.229
Content-Type: text/plain; charset=ISO-8859-1
Content-Transfer-Encoding: 8bit
X-Trace: posting.google.com 1029155367 22018 127.0.0.1 (12 Aug 2002 12:29:27
 GMT)
X-Complaints-To: groups-abuse@google.com
NNTP-Posting-Date: 12 Aug 2002 12:29:27 GMT
Xref: archiver1.google.com comp.lang.ada:27945
Date: 2002-08-12T12:29:27+00:00
List-Id: <comp.lang.ada>

Have look at the following program 
with TEXT_IO; 
with UNCHECKED_CONVERSION; 
procedure UNCHECK_DEMO is 
package INT_IO is new TEXT_IO.INTEGER_IO(LONG_LONG_INTEGER); 
function INT_TO_FLT is 
new UNCHECKED_CONVERSION( 
SOURCE => LONG_LONG_INTEGER, 
TARGET => FLOAT); 
INT : LONG_LONG_INTEGER; 
FLT : FLOAT; 
begin 
INT:=2#11111111100000000000000000000000#; 
FLT:=INT_TO_FLT(INT); 
INT_IO.put(INT,0,2); 
end; 

Now look at the following sentences which explains how to find the
exact value of a 32 bit word (This 32 bit word is IEEE single
precision floating point standard representation).

The value V represented by the word may be determined as
follows:(Concentrate on condition 2).

1)If E=255 and F is nonzero, then V=NaN ("Not a number") 
2)If E=255 and F is zero and S is 1, then V=-Infinity 
3)If E=255 and F is zero and S is 0, then V=Infinity 
4)If 0<E<255 then V=(-1)**S * 2 ** (E-127) * (1.F) where "1.F" is
intended to represent the binary number created by prefixing F with an
implicit leading 1 and a binary point.
5)If E=0 and F is nonzero, then V=(-1)**S * 2 ** (-126) * (0.F) These
are "unnormalized" values.
6)If E=0 and F is zero and S is 1, then V=-0 
7)If E=0 and F is zero and S is 0, then V=0 
Now in the above program I am making the float variable FLT to take
the value so as satisfy the condition 2. I was expecting exception to
be raised when i run this program(because the value should be infinity
according to condition 2), but it did'nt.
Any Idea why?Pls let me know if I am doing any stupid thing in the
program.