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Date: Sat, 7 Apr 2018 17:32:12 -0700 (PDT)
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Subject: no, it can't be,
 there's no "with procedure instance_of_generic_procedure
 is new generic_procedure;" ? Impossible !
From: Mehdi Saada <00120260a@gmail.com>
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Xref: reader02.eternal-september.org comp.lang.ada:51395
Date: 2018-04-07T17:32:12-07:00
List-Id: <comp.lang.ada>

I just realized one can't do that:

generic
with procedure instance_of_generic_procedure is new generic_procedure;
...

The rules say (my compilator is in trouble, can't try):
formal_subprogram_declaration ::=3D formal_concrete_subprogram_declaration
    | formal_abstract_subprogram_declaration
formal_concrete_subprogram_declaration ::=3D=20
     with subprogram_specification [is subprogram_default]
        [aspect_specification];
formal_abstract_subprogram_declaration ::=3D=20
     with subprogram_specification is abstract [subprogram_default]
        [aspect_specification];
subprogram_default ::=3D default_name | <> | null
default_name ::=3D name

What ?? I have trouble figuring how it could have been forgotten. Any paren=
thood for instances of generic compilation units, packages or subprograms, =
should be possible to mention. For uniformity (or Heaven, no different)'s s=
ake, also it would enable to check in particular things like:
generic
  type Item(<>);
  type Item_access is access Item;
  with procedure Free is new Unchecked_Deallocation (Item, Item_access);
package Smart_pointers ... Yes, I thought of that limitation with Jere's he=
lp with https://stackoverflow.com/questions/49660425/ada-difficulties-with-=
generics-incomplete-types-and-self-referencing-structure .

I hope I wasn't gravely mistaken, or else I'll probably never come here aga=
in because of shame...