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From: "Bob Fletcher" <fletcherr@logica.com>
Subject: Re: How to initiate part of a string?
Date: 1998/09/24
Message-ID: <01bde7ac$91707760$5330ea9e@UKP014459.logica.co.uk>#1/1
X-Deja-AN: 394336277
References: <35E171AB.75CD@ddre.dk>
 <35e2dc46.1973509@SantaClara01.news.InterNex.Net>
 <m37lzx3q8l.fsf@zaphod.enst.fr>
 <35e3675e.37587430@SantaClara01.news.InterNex.Net>
 <EACHUS.98Aug26113416@spectre.mitre.org>
 <35e45c89.12901035@SantaClara01.news.InterNex.Net>
Organization: Logica UK Limited
Newsgroups: comp.lang.ada
Date: 1998-09-24T00:00:00+00:00
List-Id: <comp.lang.ada>

can't you do:

Txt: String(1..100) := (28..31=>"abcd", Others=>' ');

or am I missing the point;

Tom Moran <tmoran@bix.com> wrote in article
<35e45c89.12901035@SantaClara01.news.InterNex.Net>...
> >  Txt : String(1 .. 100) := (1 ..  27=>' ') & "abcd" & (32 .. 100=>' ');
> vs
> >    Txt : String(1 .. 100) := (1 ..  27=>' ') & "abcd" & (1 .. 69=>' ');
> The former has the advantage of less error-prone arithmetic required
> of the writer or readers of the code.
>